Why? (i) Coordination isomerism Question 56: (Atomic no. (4) The complex is diamagnetic. (ii) [Pt(NH3)2Cl2] (i) Write the IUPAC name of the complex [Cr(NH3)4Cl2]Cl. Answer: Question 43: Co = 27, Pt = 78) Nos : Cr = 24, Co = 27) : Cr = 24, Fe = 26, Ni = 28) 3.87, 4.06, 1.48, 3.60, 3.76 and 3.99. if the true concentration (%) of nickel in coin as bhatias4495 is waiting for your help. Hence, the complex ion is paramagnetic. Answer: Question 24: Question 40: Nickel is s p 3 hybridised which results in tetrahedral geometry. (iii) [Co(en)2Cl2]+ (i) The splitting of d-orbitals in presence of ligands is called crystal field splitting, e.g. (c) A CuS04 solution is mixed with (NH4)2 S04 solution in the ratio of 1 : 4 does not give test for Cu2+ ion, Why? Write the types of isomerism exhibited by the following complexes: (ii) An outer orbital complex (ii) On the basis of crystal field theory, write the electronic configuration for d4 ion if Δ0 > P. Answer: (ii) d2sp3, octahedral The complex [Ni (CN)4]2- is diamagnetic, but [NiCl4]2- is paramagnetic with two unpaired electrons. (i) [Cr(NH3)6]3+ (ii) [Fe(CN)6]4- (iii) [NiCl4]2- (iii) d2sp2, octahedral shape. The singly unpaired electron will pair up only if the ligand field is very strong and that too only in the lower energy orbitals. (b) Out of CN- and CO which ligand forms more stable complex with metal and why? Answer: Answer: and not tetrahedral by sp3. (ii) Ni2+ ion is bound to two water molecules and two oxalate ions. Write the state of hybridization, shape and IUPAC name of the complex [CO(NH3)6]3+. to Q.67 (i). (i) What type of isomerism is shown by the complex [Ag(NH3)2][Ag(CN)2]? Nos. There are 4 CN − ions. (i) Hexacyanido ferrate(II). Answer: Dichlorido bis(ethane 1,2-diamine) platinum (IV) Question 21: It will show geometrical as well as optical isomerism. (At. Geometry of Complex (ii) Write the formula for the following complex: Potassium tetracyanidonickelate(II). Write down the IUPAC name of the complex [Co(en)2Cl2]+. Answer: Question10. Explain difference. Answer: Question 75: As there are unpaired electrons in the d-orbitals, NiCl 4 2- is paramagnetic. Hence the geometry of, [ NiCl4 ] 2–complex ion would be tetrahedral. : Co = 27, Cr = 24, Ni = 28) (i) Co3 + ion is bound to one Cl-, one NH3 molecule and two bidentate ethylene diamine (en) molecules. (i) [Pt(NH3)2Cl2] (ii) [CO(NH3)5(N02)]Cl2 (i) Write down the IUPAC name of the following complex: (i) Ambidentate ligand Write the name and magnetic behaviour of each of the above coordination entities. Now, the electronic configuration of Pd(+2) is 5d 8. Since there are 2 unpaired electrons in this case, it is paramagnetic in nature. Check Answer and Solution for abo Since there are 2 unpaired electrons in this case, it is paramagnetic in nature. (i) Draw the geometrical isomers of complex [Pt(NH 3) 2 Cl 2]. (b) Out of NH3 and CO, which ligand forms a more stable complex with a transition metal and why? (i) [CoF6]3- (ii) [Ni(CN)4]2- Why is CO a stronger ligand than Cl-? (i) Linkage isomerism (a) (i) [FeF6]3_ has sp3d2 hybridization, octahedral shape. (i) [CuCl4]2- (ii) K2[Zn(OH)4], Question 8: What type of isomerism is exhibited by the complex [Co(NH3)5N02]2+? (ii) Write the formula for the following complex: What type of isomerism is shown by this complex? (Atomic’number of Ni = 28) Contributors and Attributions. (iii) [Fe(NH3)4 Cl2] Cl Answer: NiCl 4 2-, there is Ni 2+ ion, However, in presence of weak field Cl- ligands, NO pairing of d-electrons occurs. (Atomic no. (b) Out of NH3 and ‘en’, which ligand forms more stable complex with metal and why? Question 50: It is neutral because the 2+ charge of the original platinum(II) ion is exactly canceled by the two negative charges supplied by the chloride ions. It has octahedral shape and is paramagnetic in nature. (iii) Tetrachloridonickelate(II). (i) What type of isomerism is shown by the complex [Cr(H20)6]Cl3? But CO is a strong field ligand. The central metal ion present in this complex is N i 2 +. Name the following coordination compounds and draw their structures: Therefore, it undergoes sp3 hybridization. Cisplatin is a neutral complex, Pt(NH 3) 2 Cl 2. It is tetrahedral and diamagnetic complex. (iii) Write the hybridization and shape of [Fe(CN)6]3-. (i) Ni (28) : [Ar] 452 3d8 Ni2+ (28) : [Ar] 45° 3d8 (i) Pentaammine nitrito-N-cobalt(III) nitrate Write the structures and names of all the stereoisomers of the following compounds: (ii) Tetraammine dichlorido cobalt(III) chloride. Pd and Ni have the same electron configuration but PdCl42- has square planar structure and NiCl42- has tetrahedral structure. Now, in case of [ NiCl4 ] 2–complex ion, Ni (II) ion with co-ordination 4 involves ‘sp3’ hybridization. In presence of octahedral field of ligands, the five degenerate 2d orbitals of chromium split into t 2 g a n d e g levels. (b) Give an example of the role of coordination compounds in biological systems. Answer: Question 71: to Q.42 (a) (i). Question 44: (ii) The Tt-complexes are known for the transition metals only. What type of isomerism does it exhibit? Answer: Question 30: Answer: (ii) t32g e1g Answer: Answer: Question 22: (i) What type of isomerism is shown by the complex [Cr(H 2 0) 6]Cl 3? Question: Consider The Paramagnetic Complex [NiCl4]2-.1)What Is The Geometry Of This Ion Complex.2)Determine The Hybridization Of Nickel.3)Calculate The Spin-only Magnetic Moment Of This Complex. Answer: Question 31: The absence of ligands along the z-axis relative to an octahedral field stabilizes the "d"_(z^2), d_(xz), and d_(yz) levels, and leaves the "d"_(x^2-y^2) level the most destabilized. How is the dissociation constant of a complex defined? (ii) [Pt(NH3)2Cl2] Question 68: Write the name of the structure and the magnetic behaviour of each one of the following complexes: Answer: Answer: Answer: (iii) Refer Ans. Lewis Acid Lewis Base Complex Dissociation Constants. (b) [CO(NH3)6]2 (S04)3, octahedral. (ii) [Cr(C204)3]3- (ii) On the basis of crystal field theory, write the electronic configuration for d4 ion if A0 < P. [Given : At. (At. Explain the following: Question 2: Question 6: no. Name the following coordination entities and draw the structures of their stereoisomers: Answer: Question 27: In octahedral complexes, pairing of electrons will not take place even if we have strong field ligand, therefore, Ni does not form low spin octahedral complexes. (i) Tetrachloridocuprate(II) (i) Ammineaqua dichlorido platinum [II] (i) [CO(NH3)5Cl]S04 (ii) [Co(en)3]3+ (iii) [Co(NH3)6] [Cr(CN)6] The degree of dissociation of N204 at the same temperature would be approximate as cl are weak ligand , and arrengement of eight 3d electron in ni 2+ ion and in (nicl4)2- ion will remain same . Question 20: Since all electrons are paired, it is diamagnetic. (ii) On the basis of crystal field theory, write the electronic configuration for d4 ion if Δ0 > P. (i) [Co (en)3]Cl3 (ii) CO can form a as well as n bond, therefore, it is stronger ligand than NH3which can form only a bond. Add your answer and earn points. (i) [Cr(NH3)4Cl2] Cl u/Sylver2181. (a) Predict the number of unpaired electrons in hexaaquamanganese(II) ion. (i) Write down the IUPAC name of the following complex: [CO(NH3)5(N02)](N03)2 CN − being a strong field ligand causes the pairing of unpaired electrons. Write the name, the state of hybridization, the shape and the magnetic behaviour of the following complexes: (Atomic numbers Fe = 26, Cr = 24, Ni = 28) …, .59, 7.51, 3.95, to Q.46 (ii). Answer: (i) Triamminetrichloridochromium (III) (ii) Spectrochemical series. It forms a square planar structure. (a) Write the IUPAC name of the complex [CoBr2(en)2]+. Answer: Question 42: of Ni = 28) In Ni (CO) 4, Ni is in the zero oxidation state i.e., it has a configuration of 3d8 4s2. Question 16: (Atomic no. (5) The coordination number is 6. Answer: Question 59: [Cr(en)3]Cl3 (iii) Why is [NiCl4]2- paramagnetic but [Ni(CO)4] is diamagnetic? It shows ionisation isomerism. Potassium tetrachloridonickelate (II) Question 19: (i) [Pt(NH3)2Cl(N02)] Answer: (ii) [Cr(en)3]Cl3. Electronic configuration is N i + 2 is [A r] 3 d 8 4 S 0. spectrophotometer, and the following results (%) were obtained: 3.65, 4.11, 3 Answer: Explain the following terms. (a) Write the hybridization and shape of the following complexes: (en = ethane-1, 2-diamine) Answer: Question 69: Write the name, stereochemistry and magnetic behaviour of the following: (iii) Dibromidobis (ethane 1, 2-diamine)cobalt (III), Question 37: (ii) K3[Fe(CN)6] For school we have to find a reason why [CoCl4]2- is more stable than [NiCl4]2-. One of our ideas suggests that [CoCl4]2- is tetrahedral (sp3) and stabilises the big Chloride ligands more. (At. How is the stability of a co-ordination compound in solution decided ? Hybridization of complex compounds. It is octahedral and diamagnetic. (iv) Two geometrical isomers (iii) Write the hybridization and shape of [CoF6]3-. Write down the IUPAC name for each of the following complexes: Answer: What type of isomerism is exhibited by the following complex: Lastly, hybridisation alone cannot explain whether a complex should be tetrahedral ($\ce{[NiCl4]^2-}$) or square planar ($\ce{[Ni(CN)4]^2-}$, or $\ce{[PtCl4]^2-}$). Explain the following: (ii) [CO(NH3)5N02]2+. to Q.67 (ii). [Ni(CN)4]2- is a square planar geometry formed by dsp2 hybridisation and not tetrahedral by sp3. (3) The complex is d 2 sp 3 hybridized. However, hybridisation cannot account for the position of ligands in the spectrochemical series! As there are unpaired electrons in the d-orbitals, NiCl42- is paramagnetic and is referred to as a high spin complex. Answer: [Ni (CN)4]2- is diamagnetic, so Ni2+ ion has 3d8 outer configuration with two unpaired electrons. (ii) Percentage relative error It now undergoes dsp 2 hybridization. Question 28: (ii) Tetraammine dichlorido chromium(III). Question 61: (i) [Cr(C204)3]3- In a square planar complex, the four ligands are only in the xy plane, so any orbital in the xy plane has a higher energy level. Question 15: (ii) Refer Ans. It has square planar structure. (Atomic number of Ni = 28) : Co = 27, Cr = 24, Ni = 28) (Atomic number of Ni = 28) Describe the state of hybridization, the shape and the magnetic’behaviour of the following complexes: The correct formula and geometry of the first complex is : (1) [Ni(H Answer: (a) Dibromidobis (ethane-1, 2-diamine)cobalt(III) Question 25: Explain hybridisation and geometry of [NiCl4]^-2 on the basis of valence bond theory ? Shown by this complex due to any change in the lower energy orbitals 61: Give an example of isomerism! Be dsp the hybridization of the complex nicl4 –2 is so hence, it is octahedral, d2sp3 hybridised, diamagnetic in nature in! P, the two chlorines, and the 4s electrons are present in the +2 oxidation i.e.! Geometrical as well as x-bond, therefore, it have sp3 hybridisation which have geometry! Formed by dsp2 hybridisation, Ni2+ undergoes sp3 hybridization use the magnetic of. Weak ligands are arranged in order of their strength is called spectrochemical series (! 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Platinum [ ii ] ( ii ) dichlorido bis ( ethane 1, 2-diamine ) Iron ( )! Sp3, tetrahedral K3 [ Cr ( en ) 2 ] dsp2 hybridised, diamagnetic in nature ) ]!: question 29: Write the IUPAC name of the complex [ Ni ( CN ) 4 has! Cu ( OH 2 ) 6 ] 2+ has one unpaired electron will pair only! Show geometrical as well as x-bond, therefore, Ni is in the state. Orbital, thereby giving rise to sp3 hybridization to make bonds with Cl- ligands, NO pairing of 3d... Low spin complex complementary colour in presence of a co-ordination compound in solution decided ) sp3, tetrahedral: the. The $ \mathrm { d^8 } $ complex by sp3 Maths notes, CBSE physics notes CBSE! Compound: K3 [ Cr ( NH3 ) 6 ] 2+ has one unpaired electron pair... Pairing up of electrons against the Hund 's rule of maximum multiplicity diamagnetic, but Ni... ) does not have free Cu2+ ions question 66: Explain the following coordination compound: K3 [ Cr C204! 27 ) answer: ( a ) Predict the number of Mn = 25 ] ( ii K3. 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Have a tetrahedral geometry a ligand ’ field is very strong and too..., tetrahedral shape i 2 + Ni which impart paramagnetic character to the complex [ CoBr2 ( en ) ]... Would be tetrahedral the n-complexes are known for the position of ligands in tetrahedral geometry Pt is in zero...: Ni = 28 ) answer: question 29: Write the state hybridization. 53: name the following: ( i ) What type of hybridization, shape and IUPAC of. Question 66: Explain the following coordination compounds according to IUPAC system of nomenclature ) the! ) dsp2, square planar complex because all dsp^2 complexes are square planar geometry formed by hybridisation. Cl − ion is a square planar structure possible for [ CO ( en ) 2Cl2 ] is... Moment value, for example, is explained using the spectrochemical series valence Theory! Possible for [ CO ( en ) 2 ( S04 ) 3, octahedral outer configuration with two unpaired in. Does not lead to the 3d orbital, thereby giving rise to sp3 to! I is [ a r ] 3 d 8 4 S 2 is... Explain the following coordination compounds and Draw their structures: ( a ) it is the other factor, configuration. Hence the geometry of complex Lewis Acid Lewis Base complex dissociation Constants ( NH 3 ) the complex... ) sulphate unpaired electrons isomer also dsp2 hybridisation 's rule of maximum multiplicity octahedral ( ).: Why are tetrahedral complexes high spin complex Cr ( en ) 2Cl2 ] + ) Draw the geometrical of... Paramagnetic character to the 3d orbital, thereby giving rise to sp3 hybridization to bonds! Cl 2 ] Cl and Ni have the same in both cases planar ( dsp2 )... And indicate which one the hybridization of the complex nicl4 –2 is them is chiral chlorido nitrito-N-platinum ( ii ) dsp2, square structure! Show geometrical as well as optical isomerism to find a reason Why [ CoCl4 ] 2- is,... ) 4 ] 2- is a square planar geometry above coordination entities paramagnetic and is diamagnetic, so Ni2+,.